Their finding?
结果如何呢？
The coots that couldn't tell when a stranger's egg had been stuck into their nest laid that many fewer of their own–sneak one in, the coot lays one fewer.
不能认出陌生蛋骨顶巢里的蛋越来越多，而自己的蛋越来越少K(H5]RG4)i_GT@H0w。
Sneak two in, the coot lays two fewer.
如果多出两个陌生蛋，它们就会少生两个蛋kE#+U(QM@#AHj。

Coots that successfully spotted intruders knocked them out again and then laid the same number they normally would.
而那些认出闯入者的鸟则会将其赶走，然后产下通常相同数量的蛋Lwg)L78VTN_kwk0)。
If the number of eggs laid were independent of how many the coot sees in its nest, coots that allow a stranger's egg should wind up with one egg extra.
如果产蛋数量与巢里蛋的数量是独立的，那么骨顶就会算上陌生蛋，不再生蛋rlWb&B3Sa1。
But they don't.
可是他们它们不会)i5](X*)CNk0~IaZSME6。
Lyon argues that, along with egg recognition, the coots must therefore be doing some version of I see I have nine eggs here-time to stop laying now.
里昂认为，骨顶是具有识别蛋的能力，它们可能在想已经有了九个蛋，可以停了~NPlXlik=uPHw.mPx|%J。
And that means coots count.
那就意味着它们能数数lUcdAN]@=7kB#=o。
Other researchers aren't convinced.
其他研究人员并不相信这一理论P5*.o|C99%)V6t7。
But though the debate goes on, the case for animal counting just got stronger…by the weight of one coot.
虽然争论还在继续，但权因骨顶，动物会数数的事例越来越多=iVj~s^.nV&1v。