After trying and failing to find a post office so that he could mail his sweater and pullover to his mother, who took in his non-shrink washing, he boarded the Queen Elizabeth that evening.
图灵想把毛衣和套衫寄给母亲，她会帮他清洗这些容易缩水的衣服，但他却没找到邮局，只好作罢。当天傍晚，他带着干洗包裹，登上了伊丽莎白皇后号。
This visit to the land of Oz was a very pale reflection of the liaison of just four years before.
四年之后他又来到了这片绿野仙踪，去拜访那些单调乏味的工人。
The conference had brought together almost every conceivable interested American party, but Alan was the only British participant.
这场座谈会，集合了几乎所有与计算机相关的美国人注，图灵则是唯一的英国人。
He played a large part in the discussions.
他在这场座谈中，扮演了很重要的角色，
For example, he discussed the cathode ray tube storage proposals made by J.W. Forrester and J.A. Rajchman, the latter being responsible for development of the Iconoscope at RCA.
他评论了J·W·弗来斯特和J·A·拉奇曼关于阴极射线管存储器的提议，后者正在美国无线电公司负责开发光线摄像管。
His discussion was in characteristic style, taking an engineering problem and locating a point of abstract principle that lay behind it:
图灵的评论具有他一贯的风格，也就是用抽象的理论来讨论工程问题：
Dr Turing: I do not know whether I should really ask my question of Dr Rajchman or Dr Forrester, because this difficulty arises in both papers.
图灵博士说：我不知道是否应该向拉奇曼博士和弗莱斯特博士重申我的问题，因为这个问题已经在两份论文中提出过了。
Dr Forrester mentioned that there was a possibility of reconstituting the charge by use of low velocity electrons and said that Dr Rajchman would explain it in his paper.
弗来斯特博士提到了通过低速电子来刷新电荷的可能性，并且说拉奇曼博士将会在他的论文中对此给出详细的解释。
I understand from Dr Forrester that the method should be applicable to his type of storage.
弗来斯特博士认为该方法对于他的存储器来说是可行的，
But there seems to me to be a fundamental difficulty which in principle amounts to this:
但我认为这里面似乎存在着一个根本性的困难。
unless the storage medium has some kind of association with the granular structure, such a method cannot be applicable because if any one such pattern is stable,
除非这种存储介质具有颗粒状结构，否则这种方法将不可行，因为对于任何一个稳定的状态来说，如果它是稳定的，
then by a symmetry argument, by a slight shift one way or the other, as it were, a slightly different configuration is also stable.
那么将它改变一个任意微小量而得到的状态就同样是稳定的。
Thus you do not get a finite number of stable configurations, but an infinite number.
因此，你无法给出一个有限的稳定状态数，相反，这个数将是无限的。